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CLA-VAL

X143HP

CLA

A-

X143HP

MODEL

Hydro-Powered Generator

Product Features

• Provides power by using the

pressure drop across a PRV to run

a generator

• Compact design easily adapts to

small, pre-existing vaults or new

installations

• No down time due to cloudy days

• Applications include powering

electronic control valves, RTUs,

monitoring equipment, sump pumps,

lighting; and pressure management

• Can also be used for hydro-powered

electronic monitoring

• Use one battery for 12 Volt or two

for 24 Volt requirements

• Additional batteries may be used to

store excess energy produced by

generator system

• Patent Pending

Schematic Diagram

Supplied Equipment

1 Power Generator Unit

2 Y-Strainer

3 Diversion Load

4 DC Charge Controller/Power Display

5 Circuit Breaker

Optional Equipment

A Control Valve:

• 90 Series Pressure Reducing Valve (PRV)

• or 40 Series Differential Limiting Valve

• or 49 Series Differential PRV (with sensing line)

B Isolation Ball Valve

C Battery Housing

D Gauge

Customer Supplied Equipment

6 New or existing Pressure Reducing Valve

7 Battery(ies)

- - Wiring between 1 & 4, 3 & 4, and 4 & 7

- - Tubing between 1 and 6

Power Generator Envelope Dimensions

2) Generator Unit with Y-Strainer: 7” H x 7” W x 21” L

• Generator Unit with installed control valve = 25” H

3) Diversion Load: 16” H x 9” W x 4” D

4) DC Charge Controller/Display: 20 H x 20” W x 10” D

5) Battery Housing: 10.5” H x 10.5” W x 14” D

Power Generator Specifications

• 12V DC or 24V DC

• 35 PSI minimum differential pressure required

• 50 - 250 watts generator power output

• 1.25” NTP connection

CLA-VAL

X143HP

Global Headquarters

PO Box 1325

Newport Beach, CA 92659

800.942.6326 • 949.548.5441 • www.cla-val.com

1 & 2

34C

1 2

Sommario

Pagina 1 - Hydro-Powered Generator

CLA-VALCLA-VALCLA-VALX143HPCLA-VACLLA-VVAX143HPMODELHydro-Powered GeneratorProduct Features• Provides power by using the pressure drop across a PRV t

Pagina 2 - Calculation Example

Power = Volts * Amps. To calculate necessary amps, divide the necessary power by the supplied voltage. Both the load on the sys-tem and the capacity o

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